Using the Evaporation Rate Calculator

The calculator requires five key inputs. First, enter the surface area of your water body in square metres—a 20 m² pond, for example. Next, specify the wind speed in metres per second; local weather stations or anemometers provide this value. Air temperature and relative humidity follow, both measured in standard units. The tool then computes evaporation using humidity ratios derived from psychrometric equations.

Two calculation paths are available. You can supply temperature and relative humidity directly, allowing the tool to derive the maximum humidity ratio internally. Alternatively, if you already know the current and maximum humidity ratios (common in engineering practice), enter those values instead. The result appears as kilograms per hour, which you can scale to daily or seasonal totals.

Evaporation Rate Formula

Evaporation from a water surface scales with three primary factors: the capacity of air to absorb moisture (controlled by wind and saturation), the available surface area, and the difference between saturated and actual humidity levels.

Evaporation rate (kg/h) = (25 + 19 × v) × A × (Xs − X)

where saturation humidity at temperature T:

Xs = 0.003733 + 0.00032T + 0.000003T² + 4×10⁻⁷T³

and actual humidity ratio:

X = RH × Xs

  • v — Wind velocity in metres per second; higher speeds remove moisture-laden air faster
  • A — Water surface area in square metres; larger surfaces expose more liquid to evaporation
  • Xs — Maximum humidity ratio of saturated air at the water surface temperature, in kg water vapour per kg dry air
  • X — Current humidity ratio of ambient air, calculated as relative humidity multiplied by saturation ratio
  • RH — Relative humidity as a decimal (0 to 1); lower values increase evaporation potential

Daily Evaporation Calculations

For planning purposes, multiply the hourly rate by 24 to obtain total daily evaporation, using average wind speed and humidity across the entire day:

Daily evaporation (kg) = 24 × (25 + 19 × v_avg) × A × (Xs_avg − X_avg)

  • v_avg — Average wind speed over 24 hours, in metres per second
  • Xs_avg — Average saturation humidity ratio based on mean daily temperature
  • X_avg — Average actual humidity ratio across day and night

Physical Basis of Evaporation

Evaporation occurs because water molecules possess random thermal motion. Those with sufficient kinetic energy—typically at the liquid surface—escape into the gas phase despite intermolecular attraction. The rate accelerates when the surrounding air is unsaturated, because escaped molecules do not immediately recondense.

Wind removes the thin moist boundary layer above the water, replacing it with drier air from the environment. Without air movement, humidity near the surface climbs, reducing the driving force for further evaporation. Temperature amplifies molecular motion, increasing escape rates and the air's moisture-holding capacity simultaneously. Relative humidity directly opposes evaporation: saturated air (100% RH) permits zero net evaporation, whilst dry air (20% RH) sustains vigorous evaporation.

Practical Considerations and Pitfalls

Real-world evaporation varies with factors beyond calculator inputs; account for these when planning water management.

  1. Stratification and temperature gradients — Still water develops cooler layers at depth. The formula assumes uniform temperature at the surface, but in practice, afternoon heating creates a warm upper layer that evaporates faster than the bulk temperature suggests. Measure or estimate surface temperature for greater accuracy.
  2. Wind speed variability — Weather reports often give peak gusts rather than sustained averages. Use 10-minute average wind speed, not instantaneous values. Sheltered sites (surrounded by vegetation or structures) experience lower effective wind speeds than open weather stations nearby.
  3. Seasonal humidity swings — Morning dewfall and overnight condensation can exceed hourly evaporation rates in temperate climates. The calculator assumes steady-state conditions; over multi-day periods, net loss depends on daily cycling and rainfall contributions.
  4. Salinity and mineral content — Salt water and irrigation runoff evaporate slightly slower than pure water because dissolved solids lower water vapour pressure. This effect is small (1–3%) for typical concentrations but matters for precision agricultural or industrial water balances.

Frequently Asked Questions

What is the single most important factor controlling evaporation rate?

Relative humidity exerts the dominant control. When air is saturated (100% RH), evaporation ceases entirely; when air is dry (below 30% RH), evaporation accelerates sharply. Temperature and wind speed amplify the effect, but a moisture-laden atmosphere will suppress evaporation regardless of heat or wind. This is why evaporation slows dramatically on humid, calm mornings and peaks on dry, windy afternoons.

How much water does a typical swimming pool lose per day?

A 50 m² pool in temperate summer conditions (22°C, 60% RH, 2 m/s breeze) loses roughly 8–12 kg per day, equivalent to 8–12 litres. Under hotter, drier, and windier conditions (30°C, 40% RH, 4 m/s), loss climbs to 20–25 kg daily. Over a month, this represents 250–750 litres—significant enough to require routine top-up schedules and water treatment adjustments.

Can evaporation be negative or reversed?

No, evaporation only occurs when the air is unsaturated. If the air is already saturated or supersaturated, water vapour condenses back onto the surface instead; this is dew or fog deposition. The calculator's humidity ratio difference (Xs − X) becomes zero or negative in such conditions, yielding no net evaporation. On clear, cool nights, this reversal can return 10–20% of daytime losses to the water surface.

Why does the wind speed coefficient equal 19, and where does 25 come from?

These empirical constants, derived from extensive laboratory and field studies of water surface mass transfer, represent the baseline evaporation rate (25) and the linear enhancement per unit wind speed (19). They are specific to the psychrometric assumptions underlying the formula and apply best at low to moderate wind speeds (0–10 m/s). At extreme winds above 15 m/s, surface roughness and spray effects introduce non-linearity not captured by this model.

How do I measure or estimate relative humidity at my location?

Weather stations, smartphone apps, and online forecasts report relative humidity as a percentage. For on-site measurement, use an inexpensive digital hygrometer (±3–5% accuracy) or a sling psychrometer (a manual device requiring two thermometer readings). Note that relative humidity changes with time of day and temperature; measure during the period you wish to evaluate, or use the day's average for daily evaporation estimates.

Should I account for evaporation from rain or irrigation water added to my pool?

Yes, if rainfall or hose water is frequent. The calculator predicts net evaporation from an existing body. Any water added replaces losses up to that point. For irrigation ponds or reservoirs receiving regular inflow, calculate evaporation separately and subtract from the inflow volume to determine whether the system gains or loses water over time. This is essential for agricultural water budgeting.

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